Question

Latoya, Trey, and Hans have a total of $95 in their wallets. Trey has 4 times what Hans has. Hans has $5 less than Latoya. How much do the

have in their wallets?

Answer 1

Explanation:

let , the money of

latoya = x + $5

hans = x

trey = 4x

According to question,

total amount of money = $95

or, (x +$5) + x + 4x = $95

or, 6x = $95 - $5

or, x = $90 / 6

or, x= $15

So, x + $5 = $15 + $5 = $ 20

4x = 4 × $15 = $60

Hence, layota has $20, Trey has $60 and Hans has $15.

Answer 2

Hans: 15

Trey: 60

Latoya: 20

Explanation:

Using algebra, we will solve this problem by using variables that represent the wallets of Latoya, Trey, and Hans.

Let's use x as the amount of money that is in Hans' wallet.

Let y represent the money in Latoya's wallet.

Trey: 4x, since Trey has 4 times as much as Hans.

Let's create some equations.

5x + y = 95 (total amount)

x + 5 = y (Latoya has $5 more than Hans)

Now we can use substitution with the second equation fo find x, the amount of money in Hans' wallet and 4x, the amount of money in Trey's wallet. After doing this, we can solve for y, Latoya's wallet.

y = x + 5

Substitute into the first:

5x + x + 5 = 95

6x + 5 = 95

Subtract 5 from both sides:

6x = 90

Divide by 6 to solve for x:

x = 90/6

x = 15

We have the amount of money in Hans's wallet, $15. We know that Trey has 4 times as much, so he has 4 * 15 = $60 in his wallet. Hans has $5 less than Latoya, so we add 5 to 15 to get 5 + 15 = $20 in Latoya's wallet.

Why don't we check to see if our answers work here:

Hans: x = 15

Trey: 4x = 60

Latoya: y = 20

15 + 60 + 20 = 95

Correct!