Answer:

Explanation:
1. Whenever you write a quadratic function with zeros, you want to put it into a formula like this:

p and q are the zeros
2. Your zeros are (-3) and (-10). When plugging in the zeros, you always flip the sign on the number. Because you would plug it in as:

Two negative signs equal positive signs, so the equation will look like this:

3. Solve the equation:
a. Use the foil method:


b. Collect like terms

c. Simplify

Hope that helps!