Question

HALP ME PLS E-x-p-la-i-n how you got your answer plsssssss i neeed to know this cr9p

Answer 1

`\sf y = (-2)/(5)x+1`

Explanation:

Equation of the line: y = mx + b

Where m is the slope and b is y-intercept.

(5, -1) & (-5, 3 )

`\sf \boxed{Slope=(y_2-y_1)/(x_2-x_1)}`

`\sf =(3-[-1])/(-5-5)\\\\=(3+1)/(-10)\\\\=(-4)/(10)\\\\=(-2)/(5)`

Substitute m = (-2/5) in the equation,

`\sf y = (-2)/(5)x+b\\\\Now, substitute \ any \ point \ in \ the \ above \ equation \ and find \ 'b',\\\\(5,-1)\\\\ -1 = (-2)/(5)*5+b\\\\-1=-2+b\\`

-1 + 2 = b

`\sf \boxed{b = 1}\\\\\bf The \ equation \ of \ the \ line, \\\\ \ y =(-2)/(5)x+1`