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What is an equation of the line that passes through the points (2, 6) and ( -2, -4)?

1 Answer

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Answer:

y = (5/2)x + 1 or

y = 2.5x + 1

Explanation:

The slope-intercept form of the equation of a line is

y = mx + b

where m = slope, b = y-intercept

Slope = rise / run

where rise is the difference in y-values of two points on the line and run = difference in x values for the same two points'

Here the points are (2, 6) and (-2, -4)

rise = 6 - (-4) = 6 + 4 = 10

run = 2 - (-2) = 2 + 2 = 4

Slope = 10/4 = 5/2

Equation is

y = (5/2))x + b

To calculate b, plug in x, y values for (2, 6) to get
6 = (5/2) x 2 + b

6 = 5 + b

b = 6 - 5 = 1

Equation of line is

y = (5/2)x + 1

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