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Simplify the expression so that it is expressed in terms of cosine to the first degree:


-\mathrm{sin}((x)/(2))

User Inline
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Answer:


{ \tt{ - \sin(2x) = - 2 \sin(x) \cos(x) }}

- The above formular is the identity of sine double angles


- { \tt{ \sin( (x)/(2) ) = - 2 \sin( (x)/(4) ) \cos( (x)/(4) ) }} \\ \\ { \boxed{ \tt{ \sin( (x)/(2) ) = 2 \sin( (x)/(4) ) \cos( (x)/(4) ) }}}

User Bluepnume
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