A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is the cliff, if it took 16.4 s for the ball to reach the ground?

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Ctsears asked Jan 27, 2022

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A ball is thrown vertically up from the edge of a cliff with a speed of 8 m/s, how high is

the cliff, if it took 16.4 s for the ball to reach the ground?

Physics
college

Ctsears asked Jan 27, 2022

by Ctsears

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Step-by-step explanation:

s=d/t

d=s×t

d=8×16.4

d=131.2

distance is 131.2m.

Thomas Keller answered Feb 2, 2022

by Thomas Keller

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