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Find the equation of the line passing
through the points (4, 2) and (6, 10).
y=[?]x+[ ]

User Jarauh
by
8.0k points

1 Answer

4 votes

Answer:

y = 4x - 14

Explanation:

The equation of a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0).

We can calculate the slope with the two given points. Slope is the Rise/Run between these 2 points:

(4,2) and (6,10)

Rise: 10 - 2 = 8

Run: 6 - 4 = 2

Slope = Rise/Run = 8/2 = 4

m is 4, so we can write: y = 4x + b

We can find b by entering either of the given points and solving for b. I'll use (4,2):

y = 4x + b

2 = 4*(4) + b

2 = 16 + b

b = -14

The equation becomes y = 4x - 14

See the attached graph.

Find the equation of the line passing through the points (4, 2) and (6, 10). y=[?]x-example-1
User Darrian
by
8.6k points

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