Question

Please help me

how law of motion applied in basketball need step by step explain ​

Answer 1

- Assume a player s meters dunks a ball at an angle theta at an initial velocity Vo, through a net h meters from the ground.

- From Newton's first law of motion; a body remains in its state of motion unless acted upon by an external force.

`{ \rm{v = u + at}}`

- Since it undergoes projectile motion, there is both vertical and horizontal motion;

Vertical motion:

`{ \rm{v _(y) = u _(y) - gt }} \\ { \rm{v \sin( \theta) = u \sin( \theta) - gt }}`

- To find the vertical displacement moved by the ball. Let H be the vertical displacement moved by the ball

`{ \rm{H =( u \sin( \theta) - (1)/(2) g {t}^(2) ) + h}} \\ \\ { \rm{}}`

Horizontal motion (g = 0);

`{ \rm{v _(x) = u _(x) }} \\ \\ { \rm{s = u \cos( \theta) t}}`