Question

100 POINTS!

A gas with a pressure of 2.25 atm occupies 450.0 mL at a temperature of 300 K. What is the volume at 405.0 K?


a
333.3 mL
b
270.0 mL
c
750.0 mL
d
607.5 mL

Answer 1

D) 607.5 mL

Step-by-step explanation:

Combined Gas Law: P1V1/T1=P2V2/T2

Substitute: [2.25(450)]300=[2.25(V)]/405

Solve for V: 3.375=2.25V/405

3.375(405)=2.25V

1366.875=2.25V

V=607.5 mL