Solve for j. 2j² + 17j = 0 j=

asked Aug 23, 2023 148k views

4 votes

Solve for j.
2j² + 17j = 0
j=

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7 votes

Answer: j = 0 or j = -17/2

Work Shown:

$2j^2 + 17j = 0\\\\j(2j + 17) = 0\\\\j = 0 \ \text{ or } \ 2j + 17 = 0\\\\j = 0 \ \text{ or } \ 2j = -17\\\\j = 0 \ \text{ or } \ j = -17/2\\\\$

Side note: -17/2 = -8.5 in decimal form

Jornathan answered Aug 26, 2023

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