Question

An object accelerates from rest to a speed of 24 m/s over a distance of 56 m. What

acceleration did it experience?

Answer 1

5.14 m/s^2

Step-by-step explanation:

v * t = distance AVERAGE velocity = (24-0) / 2 = 12 m/s

distance / v = time

56 m / 12 m/s = 4.67 s

vf = at

24 = a ( 4.67) a = 5.14 m/s^2