Question

what quantity of heat energy is needed to melt 120g of ice at -20°C to water at 30°c? (SHC of water = 4200J/kg/k, SHC for ice = 2100J/kg/K, Specific latent heat of fusion of ice = 3.36x10^5 J/kg)​

Answer 1

59, 720 Joules

Step-by-step explanation:

`q = mc(t2 - t1) + m(lf) + mc(t2 - t1)`

first term=ice to 0 degrees

second term=water to ice

third term-water to 30 degrees

`q = 0.12 * 2100 * 20 + 0.12 * 3.36 * {10}^(5) + 0.12 * 4200 * 30`

`q = 59720 \: joules`