Helppp 7 √(?) = 55 Plsss (5)/(10) = what ​

Question

Helppp

`7 √(?) = 55`
Plsss

`(5)/(10) = what`
​

Answer 1

The first questions unknown equals

`(3025)/(49)`

The second question is unclear. I assume it is to simplify if that is the case the answer will be.

`(1)/(2)`

Explanation:

First Question I made ?=x for simplicity.

`7 √(x) = 55`

then I divide both sides by 7

`√(x) = (55)/(7)`

then I square both sides

`x = (3025)/(49)`

Question 2

I simplified by dividing both the denominator and the numerator by their HCF (highest common factor) which is 5

`(5 / 5)/(10 / 5)`

which equals

`(1)/(2)`

Answer 2

`\textsf{1.} \quad 7\sqrt{(3025)/(49)}=55`

`\textsf{2.} \quad (5)/(10)=(1)/(2)`

Explanation:

Question 1

Let x be the unknown number:

`\implies 7√(x)=55`

Divide both sides of the equation by 7:

`\implies (7 √(x))/(7)=(55)/(7)`

`\implies √(x)=(55)/(7)`

Square both sides of the equation:

`\implies \left(√(x)\right)^2=\left((55)/(7)\right)^2`

`\implies x=(55^2)/(7^2)`

`\implies x=(3025)/(49)`

Question 2

Divide the numerator and the denominator by the highest common factor:

`\implies (5 / 5)/(10 / 5)=(1)/(2)`