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If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)

User Sul Aga
by
7.8k points

1 Answer

3 votes

If we write
k where we see
x in the equation and set the result equal to
-10, we get the result.


  • f(k)=k(k)^3+k^2-k(k)+2

  • =k^4+k^2-k^2+2

  • =k^4+2=-10

  • k^4=-12

  • k_(1)=\sqrt[4]{3}(-1-i)

  • k_(2)=\sqrt[4]{3}(-1+i)

  • k_(3)=\sqrt[4]{3}(1-i)

  • k_(4)=\sqrt[4]{3}(1+i)

User Vaughany
by
8.9k points

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