S+o2=so2 (balance)
C+o2=co2 (balance)
CuO+H2SO4=CuSO4+H2o (balance)
Answer:
S + 02= S0 - 4 e- → SIV (oxidation); 2 O0 + 4 e- → 2 O-II (reduction)
C + 02= C
Cu0 + H2SO4= CuO + H2SO4 → CuSO4 + H2O
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