What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)

asked May 20, 2023 26.9k views

5 votes

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6 votes

Answer:

dt=20.08

Step-by-step explanation:

Q=msdt

840=10*4.184*dt

dt=840/(10*4.184)

dt=20.08

Appsecguy answered May 27, 2023

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