A student measured the string as 2.43 m long. The teacher said it was actually 2.12 m long. What was the student's percent error?

asked Feb 7, 2023 32.8k views

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A student measured the string as 2.43 m long. The teacher said it was actually 2.12 m long.

What was the student's percent error?

by Iyuna

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Percent error = Actual observed value - expected value / expected value.
= 2.43-2.12/2.12 * 100 = 14.6226% error

Phoexo answered Feb 11, 2023

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