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If p(x) = 42x^2 - 18 and p(x) = 832.5 then what are two possible values for x?​

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If p(x) = 42x^2 - 18 and p(x) = 832.5 then what are two possible values for x?​ (Explain-example-1
User Scott Colby
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2 Answers

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This is the answer !!!!!!!!!!!!!!!!
If p(x) = 42x^2 - 18 and p(x) = 832.5 then what are two possible values for x?​ (Explain-example-1
User JCBiggar
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Answer:


\displaystyle x = 4.5 \text{ or } x = -4.5

Explanation:

We are given the function:


\displaystyle p(x) = 42x^2 - 18

Given that p(x) = 832.5, we want to determine two possible values of x.

We can substitute:


\displaystyle (832.5) = 42x^2 - 18

Adding 18 to both sides yields:


\displaystyle 42x^2 = 850.5

And dividing both sides by 42 yields:


\displaystyle x^2 = (850.5)/(42) = (81)/(4) = 20.25

We can take the square root of both sides. Since we are taking an even root, we will need plus/minus. Hence:


\displaystyle x = \pm √(20.25) = \pm4.5

In conclusion, x = 4.5 or x = -4.5.

User Minaz
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