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Write the equation of the line that is perpendicular to y = 1 and goes through (4, −9).

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FOR PERPENDICULAR LINES WHEN THEIR GRADIENTS ARE MULTIPLIED THEY GIVE -1

BUT IF WE ARE TO CHECK IN THE LJNE y=1 the gradient is 0

there is no number when multiplied with 0 that will give us -1 it means that the gradient of the line perpendicular to the given one will also be 0

when we substitute in the general equation y=mx+c together with the points


- 9 = (0)(4) + c \\ c = - 9

IT MEANS THE EQUATION OF THE NEW EQUATION WILL BE


y = - 9

HOPE THIS HELPS

User Hatsumi
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