Answer:
f−1(x)=ex+11−2ex
Explanation:
Let y=f(x)=ln(x−1)−ln(2x+1). ⇒y=ln(x−12x+1). ⇒x−12x+1=ey. ⇒2xey+ey=x−1. ⇒x(1−2ey)=ey+1.
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