Question

The functions s and t are defined as follows.

s(x) = -x+1
t(x)=x2-1
Find the value of s(t(2)).
s(t (2)) =

The 2 next to the x is an exponent

Answer 1

`s(x) = - x + 1 \\ t(x) = {x}^(2) - 1 \\ s(t(x)) = - ({x}^(2) - 1) + 1 \\ = - {x}^(2) + 1 + 1 \\ = 2 - {x}^(2) \\ s(t(2)) = 2 - {2}^(2) \\ \boxed{s(t(2)) = - 2}`