Answer:
Parental chromosomes A----b and a-----B when fertilized with ab will produce AabB and aaBb - these will be progeny with parental chromosome --- so no recombination.
You are told that map distance is 20cM which is also telling you that recombination frequency is 20% , so % progeny showing recombination = 20%, so % progeny not showing recombination is 100= 20 = 80%. This will be composed of the 2 parental categories, as above so % aaBb = 40%
Step-by-step explanation: