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Solve for b. a = 9 b² c b=±a√3c ​b=±ac√9​ b=±ac√3c b=±3ac−−√
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18 votes
Solve for b.

a = 9 b² c




b=±a√3c

​b=±ac√9​

b=±ac√3c

b=±3ac−−√

User Jonathan Bouloux
by
3.6k points

2 Answers

7 votes

b=+ac sqrt 3c

it's b=+ac sqrt 3c

User Ryan Kearney
by
3.3k points
3 votes
b=+ac sqrt 3c
(3rd option!!)
User Reza Ahmadi
by
3.4k points
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