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a 100 kg crate is being pulled across the floor at a constant velocity with a rope that makes an angle of 40 degrees to the horizontal. if the force applied is equal to 300 n, what is the force of friction acting on the box

User Hatcyl
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1 Answer

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The force of friction would be the kilograms times the velocity which equals 300n. Then 40 degrees times the kilogram an velocity amount. Then there you have the force of friction. This amount u get should equal 300n.
User Cadvena
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