Newton's Second Law.
We have the following data, provided in the exercise:
Mass (m) = ?
Force (F) = 13607 N
Acceleration (a) = 2.9 m/s²
To calculate the mass, we solve the following formula:
![\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ (F)/(a)=\frac{m*\\ot{a}}{\\ot{a}} } \end{gathered}$}}](https://img.qammunity.org/2023/formulas/physics/college/zgor4xhkq7apjvo567jf94l7x048wwkjks.png)
![\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{(F)/(a)=m \ \iff \ Address \ is \ changed \Rightarrow \ m=(F)/(a) } \end{gathered}$}}](https://img.qammunity.org/2023/formulas/physics/college/nn5e05y4a863jbx9r1zmpqu118l0rg90n7.png)
We substitute the data in the clear formula.
![\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=(13607 \ N)/(2.9 \ (m)/(s^(2) ) ) } \end{gathered}$} }](https://img.qammunity.org/2023/formulas/physics/college/33n7ppklvzj6doff9pb38mgceh1gei5i0f.png)
We break down the units of Newton = Kg * m/s².
![\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\\ot{(m)/(s^(2)) } }{2.9 \\ot{(m)/(s^(2)) } } } \end{gathered}$} }](https://img.qammunity.org/2023/formulas/physics/college/d0xx4mp2dw45w9d8wgys2j25iabkt7m78y.png)
The mass of the truck is: 4692.07 Kilograms (Kg).