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Solve the equation.

x^2 + 7x = 0

User Zrajm
by
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2 Answers

3 votes


\quad \huge \quad \quad \boxed{ \tt \:Answer }


\qquad \tt \rightarrow \:x = 0\:\; or \:\: x = -7

____________________________________


\large \tt Solution \: :


\qquad\displaystyle \tt \rightarrow \: {x}^(2) + 7x = 0


\qquad\displaystyle \tt \rightarrow \: {x}(x + 7) = 0

There are two cases now,

Case 1 :


\qquad\displaystyle \tt \rightarrow \: x = 0

Case 2 :


\qquad\displaystyle \tt \rightarrow \: x + 7 = 0


\qquad\displaystyle \tt \rightarrow \: x = - 7

So, the possible values of x are :


\qquad\displaystyle \tt \rightarrow \: 0 \: \: and \: \: - 7

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

User Caspar Harmer
by
7.9k points
2 votes

Answer:


x=0, \quad x=-7

Explanation:

Given equation:


x^2+7x=0

Factor x from the left side of the equation:


\implies x(x+7)=0

Using the Zero Product Property, set each factor equal to zero and solve for x:


\implies x=0


\implies x+7=0 \implies x=-7

Therefore, the solutions of the equation are:


x=0, \quad x=-7

Zero Product Property: If a⋅b = 0 then either a = 0 or b = 0 (or both).

User Wombatonfire
by
8.2k points

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