Question

asked Oct 1, 2023 154k views

2 Answers

Caspar Harmer · Answer 1 · 2023-10-03T21:27:48+0000

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = 0\:\; or \:\: x = -7$

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$\large \tt Solution \: :$

$\qquad\displaystyle \tt \rightarrow \: {x}^(2) + 7x = 0$

$\qquad\displaystyle \tt \rightarrow \: {x}(x + 7) = 0$

There are two cases now,

Case 1 :

$\qquad\displaystyle \tt \rightarrow \: x = 0$

Case 2 :

$\qquad\displaystyle \tt \rightarrow \: x + 7 = 0$

$\qquad\displaystyle \tt \rightarrow \: x = - 7$

So, the possible values of x are :

$\qquad\displaystyle \tt \rightarrow \: 0 \: \: and \: \: - 7$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Wombatonfire · Answer 2 · 2023-10-07T14:37:49+0000

Answer:

$x=0, \quad x=-7$

Explanation:

Given equation:

x^2+7x=0

Factor x from the left side of the equation:

$\implies x(x+7)=0$

Using the Zero Product Property, set each factor equal to zero and solve for x:

$\implies x=0$

$\implies x+7=0 \implies x=-7$

Therefore, the solutions of the equation are:

$x=0, \quad x=-7$

Zero Product Property: If a⋅b = 0 then either a = 0 or b = 0 (or both).

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