Question

a 22-g bullet traveling 240 m/s penetrates a 1.7 kg block of wood and emerges going 125 m/s .if the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?

Answer 1

m v1 = M V + m v2 conservation of momentum

V = m (v1 - v2) / M

V = .022 (240 - 125) / 1.7 = 1.49 m/s