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If g(x) = 5(x²+1) + 16, what is the value of g(11) ?​
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If g(x) = 5(x²+1) + 16, what is the value of g(11) ?​

User Tgirod
by
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1 Answer

4 votes

Answer:

626

Explanation:

11^2= 121

121+1=122

122x5=610

610+16=626

hope this helped

User Dhruv Ramani
by
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