Answer:
m∠TQS = 137°
m∠RQS = 43°
Explanation:
It is given that ∠RQT is a straight angle
That means that this angle is 180° and RQT is a straight line
Therefore m∠TQS + m∠RQS = m∠RQT = 180°
Given
m∠TQS = (6x + 20)° and m∠RQS = (2x + 40)°
adding the two angles together will imply
(6x + 20)° + (2x + 40)° = 180°
=> 6x + 20 + 2x + 4 = 180
=> 6x + 2x + 20 + 4 = 180
=> 8x + 24 = 180
=> 8x = 180 - 24= 156
=> x = 156/8 = 19.5
Substitute for x in the angle expressions
m∠TQS = 6x + 20 = 6(19.5) + 20 = 117 + 20 = 137°
m∠RQS 2x + 4 = 2(19.5) + 4 = 39 + 4 = 43°
(or we could subtract m∠TQS from 180 to get 180 - 137 = 43°)
Check if they add up to 180°
137° + 43° is indeed 180°