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1 vote
4-2(5x-1)>5x+3 how do I solve this

User Jarlax
by
8.1k points

1 Answer

5 votes
X<1/5 is the answer 4

2
(
5
x

1
)
>
5
x
+
3
4

2
(
5


1
)
>
5

+
3
4

10
x
+
2
>
5
x
+
3
4

1
0

+
2
>
5

+
3
2
Add the numbers
4

10
x
+
2
>
5
x
+
3
4

1
0

+
2
>
5

+
3
6

10
x
>
5
x
+
3
6

1
0

>
5

+
3
3
Rearrange terms
6

10
x
>
5
x
+
3
6

1
0

>
5

+
3

10
x
+
6
>
5
x
+
3

1
0

+
6
>
5

+
3
4
Subtract
6
6
from both sides

10
x
+
6
>
5
x
+
3

1
0

+
6
>
5

+
3

10
x
+
6

6
>
5
x
+
3

6

1
0

+
6

6
>
5

+
3

6
5
Simplify
Subtract the numbers
Subtract the numbers

10
x
>
5
x

3

1
0

>
5


3
6
Subtract
5
x
5

from both sides

10
x
>
5
x

3

1
0

>
5


3

10
x

5
x
>
5
x

3

5
x

1
0


5

>
5


3

5

7
Simplify
Combine like terms
Combine like terms

15
x
>

3

1
5

>

3
8
Divide both sides by the same factor, and flip the relation because the factor is negative

15
x
>

3

1
5

>

3

15
x

15
<

3

15

1
5


1
5
<

3

1
5
9
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
x
<
1
5

<
1
5
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User Daniel Lichtblau
by
7.8k points

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