Question

62.2 percent Hf by mass and 37.4 percent Cl by mass. What is the empirical formula for this compound?

Answer 1

HfCl3

Step-by-step explanation:

Step 1: Find the compounds relative atomic mass

Step 2: Divide the percentage given by the relative atomic mass

Hf = 62.2/178.5 CI = 37.4/35.5

Hf = .348 CI = 1.054

Step 3: Divide every given number by its lowest ratio. (0.348)

Hf - .348/.348 CI - 1.054/.348

Hf= 1 CI = 3

This means, the empirical formula for this compound would end up being

HfCI3.

Hope this helps!