Question

MATH
MATH
Please help been on this problem all day

Answer 1

See below

Explanation:

Use prime number factoring of the number you have within the cubed root equation.....216.

Start with 216 and find a prime number that can divide into 216 evely.

2 x 108 the 2 is a prime number

now find another prime to divide into 108 evenly.

2 x 54 again the 2 is a prime number

find another prime number that will divide into 54

2 x 27 again the 2 is a prime number

another prime that divides into 27 evenly

3 x 9 and the 3 is prime

lastly, another prime to divide into 9

3 x 3 and other of these are primes.

So if you line up these prime numbers you have 222333

Take the numbers that you have in groups of 3s. You have 1 group of 2s and 1 group of 3s. Multiply those two numbers together.

2 x 3 = 6

So the cubed root of 216 is 6.

Answer 2

Write ³√ 216 in exponential form with the base of 6
Which gives you ³√ 6 ³
Reduce the index of radical and exponent with 3
= 6

In short

³√ 216
= ³√ 6 ³
=6

Hope this helps