Question

Find the slope of any line perpendicular to the line through (4,0) and (-6,1)

Answer 1

`\sf(1)/(10)`

Explanation:

We need to find out the slope of the line perpendicular to the given points . We know that ,

`\sf: \implies Slope =(y_2-y_1)/(x_2-x_1) \\\\\sf : \implies Slope = (-6-4)/(1-0) \\\\\sf : \implies Slope =(-10)/(1) \\\\\sf : \implies \boxed{\sf Slope = -10}`

Again we know that the product of slopes of two perpendicular lines is -1 . Therefore ,

`\sf: \implies m_(perp)= (-1)/(-10)\\\\\sf : \implies \boxed{\boxed{\sf\pink{ Slope_(perp)= (1)/(10)}}}`