Step-by-step explanation:-
By Using Alternative Method :-
We know that
Factor Theorem
If x-a is a factor of P(x) then P(a) = 0
P(x) = 2x^3-4x^2-7x-10.
g(x) = x-5
Substitute x = 5 in equation.
P(5) = 2(5)^3-4(5)^2-7(5)-10.
⇛ P(5) = 2(5*5*5)-4(5*5)-7(5)-10
⇛ P(5) = 2(125) - 4(25) - 7(5) - 10
⇛ P(5) = 250 - 100 - 35 - 10
⇛ P(5) = 250 - 100 - 45
⇛P(5) = 250 - 145
⇛P(5) = 105
Since, P(5) is not equal to zero then x-5 is not a factor of 2x^3-4x^2-7x-10.