Answer:
Explanation:
You want the repeating decimal cost ...
![\$3.\overline{23}](https://img.qammunity.org/2023/formulas/mathematics/high-school/fb49o9l0etkd4d4zzrr7vf1g0t9didn2fj.png)
written as a fraction and as a mixed number.
Fraction
One can convert the repeating decimal to a fraction by multiplying it by a power of 10 equal to the number of repeating digits.
This cost number (C) has 2 repeating digits (23), so we want to multiply it by 10^2:
![100C=10^2*3.23\overline{23}=323.\overline{23}](https://img.qammunity.org/2023/formulas/mathematics/high-school/imorao0vjxgv4022iw67qhhav87f3c0u4x.png)
Now, we can subtract the original cost to cancel the repeating decimal fraction:
![100C -C = 323.\overline{23}-3.\overline{23}=320](https://img.qammunity.org/2023/formulas/mathematics/high-school/kdd1st10kzjl8a8zf83yq794wewqerfnq6.png)
Dividing by the coefficient of C, we have the fraction we want:
![C=\boxed{(320)/(99)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/wd3fogjvc1kb5w3r6ridevmeuw5ytt22j1.png)
Mixed number
This is expressed as a mixed number by figuring the quotient and remainder.
![(320)/(99)=\boxed{3(23)/(99)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/g4jko7gb277o2yh6mbmdf1gagacwzu0iqv.png)