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Find two consecutive integers such that 3 times the larger exceeds twice the smallest by 34
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Find two consecutive integers such that 3 times the larger exceeds twice the smallest by 34

User Thomas Maurel
by
6.1k points

1 Answer

1 vote

Answer:

31 & 32

Explanation:

3 x 32 = 96

2 x 31 = 62

62 + 34 = 96

User Tomloprod
by
7.4k points
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