Answer: x = -2 y = 2
Explanation:
There are different ways to solve systems of equations. I will set them equal to each other.
First, I have to divide 2 from both sides of the first equation, which gives
y = -4x - 6
Now I can set them equal to each other and solve for x.
-4x - 6 = 2x^2 + 4 x + 2
0 = 2x^2 + 8x + 8
Now we factor it. If you cannot see the factors right away, you can use the quadratic formula, but I see that
(2x+4)(x+2) = 2x^2 + 8x + 8 = 0
so, because (2x+4)(x+2) = 0, one (or both) of the parenthesis must equal zero.
Solve for each parenthesis.
2x+4=0 => 2x = -4 => x = -2
x+2=0 => x = -2
As we see here, there is only one value for x. Now we can plug it into either one of the original equations. I'll do the first since there are no squares.
2y = -8(-2) -12
2y = 16 - 12
2y = 4
y = 2