Answer:
Explanation:
Rewrite the equation in the form y=mx+b, where m is the slope.
2x+3y = 12
3y = -2x+12
y= -(2/3)x+4
A perpendicular line witll have a slope that is the negative inverse of the reference line. The negative inverse of -(2/3) is (3/2),
The perpendicular line will have the form y = (3/2)x + b
Find b by using the given point, (2,6)
y = (3/2)x + b
6 = (3/2)*2 + b
6 = 3 + b
b = 3
The equation of the line that is perpendicular to the line 2x+3y=12 and that's also passes through the point (2,6) is y = (3/2)x + 3.