Can someone please help solve this math problem with solution? thank u!

Question

asked Oct 16, 2023 64.6k views

1 Answer

Amrinder Arora · Answer 1 · 2023-10-21T18:44:09+0000

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Work Shown:

$(n^2+n-6)/(n-2)\\\\((n+3)(n-2))/(n-2)\\\\n+3$

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Step-by-step explanation:

Often when simplifying, it's a good idea to factor and see what cancels (if anything does cancel).

To factor the numerator, think of two numbers that

Through trial and error, you should find the two numbers to be 3 and -2

So that's how
n^2+n-6 factors to
(n+3)(n-2) .

After this point, the (n-2) terms cancel leaving n+3 behind

We can say
$(n^2+n-6)/(n-2)=n+3 \ \ \text{when } n \\e 2$

The
$n \\e 2$ is to avoid a division by zero error.