Question

PLEASE ANSWER ASAP

A random sample of n50 ASU students shows that they spend an average of $3.17 on coffee/tea each day with standard error of about $1.11. FIND and INTERPRET a 95% confidence interval for the mean amount spent on coffee/tea by an ASU student Note: you do not have to show work on how you found your interval, but you do need to be thorough with your interpretation of the found interval.

Answer 1

so the ans is $10.43

I know I am not that smart

Step-by-step explanation:

thank you