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What are m ∠DBC, m ∠ABD, and m ∠ABC

What are m ∠DBC, m ∠ABD, and m ∠ABC-example-1
User FICHEKK
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2 Answers

20 votes
20 votes


\\ \sf\longmapsto 2x+1+4x+19=8x-10


\\ \sf\longmapsto 6x+20=8x-10


\\ \sf\longmapsto 8x-6x=20+10


\\ \sf\longmapsto 2x=30


\\ \sf\longmapsto x=15

Now

  • <DBC=4(15)+19=60+19=79
  • <ABD=2(15)+1=30+1=31
  • <ABC=79+31=110
User Rodolfo Luna
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15 votes
15 votes

Hello inquins!


\huge \boxed{\mathbb{QUESTION} \downarrow}

What are m ∠DBC, m ∠ABD, and m ∠ABC.


\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

We can see from the figure that,

∠ABC = ∠ABD + ∠DBC ------- eq. (1)

The values of the angles are given as :-

  • ∠ABC = 8x - 10
  • ∠ABD = 2x + 1
  • ∠DBC = 4x + 19

Now, let's substitute these values in eq. (1) & solve it.

∠ABC = ∠ABD + ∠DBC


\tt \: 8x - 10 =( 2x + 1) +( 4x + 19) \\ \tt 8x - 10 = 2x + 1 + 4x + 19 \\ \tt 8x - 10 = 2x + 4x + 1 + 19 \\ \tt 8x - 10 = 6x + 20 \\ \tt 8x - 6x = 20 + 10 \\ \tt \: 2x = 30 \\ \tt \: x = (30)/(2) \\ \underline{\underline{ \bf \: x = 15}}

  • The value of x is 15.

__________________

Now, let's find the measure of the angles.

  1. m ∠ABC = 8x - 10 = 8(15) - 10 = 110°.
  2. m ∠ABD = 2x + 1 = 2(15) + 1 = 31°.
  3. m ∠DBC = 4x + 19 = 4(15) + 19 = 79°.

__________________

Hope it'll help you!

ℓu¢αzz ッ

User Jagrut Sharma
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3.2k points