Question

4.00 mol co2 is placed in a 6.00 l container at a temperature where 12.3% of it decomposes. what is the value of kc for the following at this temperature?2 co2(g) equilibrium reaction arrow 2 co(g) o2(g)

Answer 1

Answer: 0.000806

Explanation: Set up the equilibrium table, find x and from there find your Kc=(Co)^2*(O2)/(O2)^2