9514 1404 393
Answer:
0.510 ft per 24-hour period
Explanation:
We can first find the change in volume in a day:
(45,000 cfs -8,000 cfs)×(3600 s/h)×(24 h/day) = 3.1968×10^9 ft³/day
The area in square feet is about ...
(225 mi²)×(5280 ft/mi)² = 6.27264×10^9 ft²
Then the rate of change of height is ...
h' = ΔV/A = (3.1968×10^9 ft³/day)/(6.27264×10^9 ft²) ≈ 0.510 ft/day
For the given flows, the lake level will rise about 0.510 feet per day.