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What is the area of a triangle with vertices at (0, −2), ​(8, −2)​ , and ​(9, 1)​ ? Enter your answer in the box. units²

User Gerbit
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1 Answer

12 votes
12 votes

Answer:

The area of a triangle is A=1/2*b*h

When we graph the vertices of the triangle on a graph, we see that the lowest points are at y=-2, and the highest point is at y=1. Therefore, our height is 3.

The base of the triangle goes from (0,-2) to (8,-2), which gives us a length of 8 for our base.

A=1/2*(8)*(3)

A=12

or

Answer:

12 square unit.

Step-by-step explanation:

Since, the area of a triangle having vertices , and is,

Here, the vertices of the triangle are (0, −2), ​(8, −2) and ​ (9, 1),

Hence, area of the given triangle is,

User SigmaOmega
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