Question

A hydraulic lift is used to lift a car. The small piston has a radius of 5 cm and the large piston has a radius of 50 cm. If a driver applies a force of 88 N to the small piston, what is the weight of the car the large piston can support?

Answer 1

F = 880 N

Step-by-step explanation:

Apply Pascal's Principle.

f / a = F / A

Because the pressure (P = F/A) is equal on both sides of the piston.

So, using the International System of Units:

f / a = F / A

88 / 0.05 = F / 0.50

F = (88/0.05) * 0.50

F = 880 N