136k views
2 votes
Can you help me solve me this math problems?

1. 200 - 7/21
2. 50 - 4/7
3. 24 1/4 - 20 3/5
4. 10 5/8 - 6 4/9
5. 6 1/2 - 5 3/4

User Armatita
by
7.6k points

1 Answer

4 votes

Explanation:

1.

200 - 7/21 = (200×21 - 7)/21 = (4200 - 7)/21 =

= 4193/21 = 599/3 = (199×3 + 2)/3 =

= 199 2/3

we could have seen that 7/21 = 1/3.

so, then this problem was

200 - 1/3 = (200×3 - 1)/3 = 599/3 = 199 2/3

(see above)

2.

50 - 4/7 = (50×7 - 4)/7 = (350 - 4)/7 =

= 346/7 = (49×7 + 3)/7 = 49 3/7

3.

24 1/4 - 20 3/5 = (24×4 + 1)/4 - (20×5 + 3)/5 =

= 97/4 - 103/5

to calculate this we need to bring both fractions to the save denominator. the LCM (lowest common multiple) of 4 and 5 is 20.

so,

97/4 - 103/5 = (97×5)/(4×5) - (103×4)/(5×4) =

= 485/20 - 412/20 = 73/20 =

= (3×20 + 13)/20 = 3 13/20

4.

10 5/8 - 6 4/9 = (10×8 + 5)/8 - (6×9 + 4)/9 =

= 85/8 - 58/9

the LCM of 8 and 9 is 72.

85/8 - 58/9 = (85×9)/(8×9) - (58×8)/(9×8) =

= 765/72 - 464/72 = 301/72 =

= (4×72 + 13)/72 = 4 13/72

5.

6 1/2 - 5 3/4 = (6×2 + 1)/2 - (5×4 + 3)/4 =

= 13/2 - 23/4

the LCM of 2 and 4 is 4.

13/2 - 23/4 = (13×2)/(2×2) - 23/4 =

= 26/4 - 23/4 = 3/4

User Jourmand
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories