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(2x-4)²=2x(x-2)+48 solve this ecuation
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(2x-4)²=2x(x-2)+48 solve this ecuation

User Sir Conquer
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1 Answer

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Answer:

x = 2, 4

Explanation:


(2x-4)^2=2x(x-2)+48 \\ \\ 4x^2 - 16x+16=2x^2-4x+48 \\ \\ 2x^2-12x-32=0 \\ \\ x^2-6x-8=0 \\ \\ (x-2)(x-4)=0 \\ \\ x=2, 4

User Pravat Panda
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