Question

Suppose a ball is dropped from a building. What is the change of velocity between the first and fifth seconds of its flight

Answer 1

Answer: 39.2m/s

Step-by-step explanation:

Due to the free falling body, the acceleration of the ball is 9.8 m/s^2, and its initial velocity is 0 m/s.

V(t) = g*t

The change of velocity from t=1 to t=5:

Delta V = 9.8*(5-1) = 39.2 m/s