Question

Represent the quadratic function please help

Answer 1

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \: y = x² -14 x + 48`

____________________________________

`\large \tt Solution \: :`

The values of x for which the curve cuts/touches the x - axis are roots of that particular polynomial.

So, the values of x, when y = 0 are the roots of the given quadratic function.

that is : x = 6 and x = 8

And it can be represented as :

`\qquad \tt \rightarrow \: (x - h1)(x - h2)= 0`

[ h1 and h2 represents roots of the quadratic function ]

`\qquad \tt \rightarrow \: (x - 6)(x - 8) = 0`

It can be further simplified as :

`\qquad \tt \rightarrow \: {x}^(2) -8x - 6x + 48 = 0`

`\qquad \tt \rightarrow \: x {}^(2) - 14x + 48 = 0`

Answered by : ❝ AǫᴜᴀWɪᴢ ❞