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The values of y varies directly with x. If x=8, when y=16. What is the value of y when x=16???

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Answer:

y = 32

Explanation:

With this problem, we will use the direct variation form, y = kx.

k = proportionality constant.

Substitute the known inputs of x = 8 and y = 16 into the direct variation form:

y = kx turns into 16 = k(8)

Get k by itself by dividing 8 on both sides:
16/8 = k

2 = k

Now that we know the k value is 2, we input everything we know into the direct variation form if x were equal to 16

k = 2

x = 16

y = kx:

y = 2(16), making y equal to 32

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